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5x/3x=(2x^2)/7
We move all terms to the left:
5x/3x-((2x^2)/7)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
-2x^2/7+5x/3x=0
We calculate fractions
We do not support expression: x^3
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